本帖最后由 Richard.Huang 于 2023-10-31 12:02 编辑
产品:SpreadJS
版本:V15.1.0
数据绑定信息列表,想自定义,就是 List里的name,age,year ...,该如何做把name,age,year 加载到数据绑定,只能把这些转成这样的吗
{
"$schema": "http://json-schema.org/draft-04/schema#",
"properties": {
"姓名": {
"dataFieldType": "text",
"type": "string"
},
"年龄": {
"dataFieldType": "text",
"type": "string"
},
"工作经历": {
"dataFieldType": "table",
"type": "array",
"items": {
"type": "object",
"properties": {
"时间": {
"type": "string"
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