【7.0】Base64转图片并上传

x1061875478 发表于 2021-9-14 11:14:13

本帖最后由 x1061875478 于 2024-7-12 09:36 编辑

看见论坛里有这个需求，做了个小demo大家一起参考

2021/10/29（链接更新）
补一个api文件：
https://www.aliyundrive.com/s/PpyzZ2AATkw
2024/07/12
此插件已经可以实现，大家就不用下这个工程了
豪~豪插件合集 - 葡萄城市场 (grapecity.com.cn)

vickdracula 发表于 2021-9-14 14:48:54

这个结合AI能做出很多场景

xiaoyeniao 发表于 2021-10-9 18:51:13

:victory:

ngqj 发表于 2021-10-28 18:20:27

大佬，求指导啊！

x1061875478 发表于 2021-10-28 18:27:35

ngqj 发表于 2021-10-28 18:20
大佬，求指导啊！

应该挺清楚的吧，有哪里不懂吗

ngqj 发表于 2021-10-29 14:16:56

x1061875478 发表于 2021-10-28 18:27
应该挺清楚的吧，有哪里不懂吗

感觉漏了些东西，达不到结果，用demo测试了一下，而且附带的那个api文件下不了

追风发表于 2024-5-22 23:28:29

api还有吗，大佬。现在打不开了

x1061875478 发表于 2024-5-23 10:50:56

追风发表于 2024-5-22 23:28
api还有吗，大佬。现在打不开了
这个比较老了清理了，可以使用这个插件功能来实现类似操作

x1061875478 发表于 2024-5-23 10:54:14

追风发表于 2024-5-22 23:28
api还有吗，大佬。现在打不开了

public async Task UpBase64Image()
{
   IFormCollection postdata = await this.Context.Request.ReadFormAsync(new CancellationToken());
   StringValues stringValues = postdata["base64Str"];
   string base64Str = ((StringValues) ref stringValues);
   base64Str = base64Str.Substring(base64Str.IndexOf(",") + 1);
   stringValues = postdata["FileName"];
   string FileName = ((StringValues) ref stringValues);
   byte[] arr = Convert.FromBase64String(base64Str);
   MyApi1.MyApi1.uploadResult result = new MyApi1.MyApi1.uploadResult();
   string assemblyLocation = Assembly.GetExecutingAssembly().Location;
   if (AppDomain.CurrentDomain.ShadowCopyFiles)
   {
   Uri uri = new Uri(Assembly.GetExecutingAssembly().CodeBase);
   assemblyLocation = uri.LocalPath;
   uri = (Uri) null;
   }
   string dir = Path.GetDirectoryName(assemblyLocation);
   DirectoryInfo theFolder = new DirectoryInfo(dir);
   DirectoryInfo path = theFolder.Parent;
   string saveFilePath = path?.ToString() + "\\GeneratedResources\\Upload";
   if (!Directory.Exists(saveFilePath))
   Directory.CreateDirectory(saveFilePath);
   string upFileName = FileName;
   char[] a = new char{ '\\' };
   string file_name = DateTime.Now.ToFileTime().ToString() + "_" + upFileName + ".jpg";
   if (file_name == "")
   {
   saveFilePath = "";
   result.code = -1;
   result.msg = "客户端文件不存在！";
   postdata = (IFormCollection) null;
   base64Str = (string) null;
   FileName = (string) null;
   arr = (byte[]) null;
   result = (MyApi1.MyApi1.uploadResult) null;
   assemblyLocation = (string) null;
   dir = (string) null;
   theFolder = (DirectoryInfo) null;
   path = (DirectoryInfo) null;
   saveFilePath = (string) null;
   upFileName = (string) null;
   a = (char[]) null;
   file_name = (string) null;
   }
   else
   {
   saveFilePath = Path.Combine(saveFilePath, file_name);
   using (MemoryStream ms = new MemoryStream(arr))
   {
      Bitmap bmp2 = new Bitmap((Stream) ms);
      bmp2.Save(saveFilePath, ImageFormat.Jpeg);
      bmp2.Dispose();
      bmp2 = (Bitmap) null;
   }
   result.code = 0;
   result.msg = "上传成功！";
   result.src = saveFilePath;
   Dictionary<string, object> values = new Dictionary<string, object>();
   string src = "/GeneratedResources/UpLoad/" + file_name;
   values.Add("图片", (object) src);
   this.DataAccess.AddTableData("表2", values);
   values = (Dictionary<string, object>) null;
   src = (string) null;
   postdata = (IFormCollection) null;
   base64Str = (string) null;
   FileName = (string) null;
   arr = (byte[]) null;
   result = (MyApi1.MyApi1.uploadResult) null;
   assemblyLocation = (string) null;
   dir = (string) null;
   theFolder = (DirectoryInfo) null;
   path = (DirectoryInfo) null;
   saveFilePath = (string) null;
   upFileName = (string) null;
   a = (char[]) null;
   file_name = (string) null;
   }
}

public class uploadResult
{
   public int code { get; set; }

   public string msg { get; set; }

   public string src { get; set; }
}这是工程里反编译出来的，跟原来的应该不一样，大致逻辑可以参考的

追风发表于 2024-5-23 11:25:09

x1061875478 发表于 2024-5-23 10:54
这是工程里反编译出来的，跟原来的应该不一样，大致逻辑可以参考的

好的，我去试试。感谢

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【7.0】Base64转图片并上传